12v^2-52v-40=0

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Solution for 12v^2-52v-40=0 equation:


Simplifying
12v2 + -52v + -40 = 0

Reorder the terms:
-40 + -52v + 12v2 = 0

Solving
-40 + -52v + 12v2 = 0

Solving for variable 'v'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-10 + -13v + 3v2) = 0

Factor a trinomial.
4((-2 + -3v)(5 + -1v)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-2 + -3v)' equal to zero and attempt to solve: Simplifying -2 + -3v = 0 Solving -2 + -3v = 0 Move all terms containing v to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -3v = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -3v = 0 + 2 -3v = 0 + 2 Combine like terms: 0 + 2 = 2 -3v = 2 Divide each side by '-3'. v = -0.6666666667 Simplifying v = -0.6666666667

Subproblem 2

Set the factor '(5 + -1v)' equal to zero and attempt to solve: Simplifying 5 + -1v = 0 Solving 5 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1v = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1v = 0 + -5 -1v = 0 + -5 Combine like terms: 0 + -5 = -5 -1v = -5 Divide each side by '-1'. v = 5 Simplifying v = 5

Solution

v = {-0.6666666667, 5}

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